Use Request Dispatcher Servlet in creating simple Login Form
We are going to create a Login Form Here. At the end of this section, you will be able to use Request Dispatcher Servlet to forward the request to another webpage based on your inputs.
Step 1:
Create a Dynamic Web Project in IDE. For Example, here I am using eclipse to create a Dynamic Web Project.
If you do not have eclipse use below link to download the eclipse for Enterprise Edition.:
https://www.eclipse.org/downloads/packages/release/kepler/sr2/eclipse-ide-java-ee-developers
Give Proper Name to your project according to you.
Here in the Target runtime (Picture below), you can see Apache Tomcat v8.5. It is Server which is required to run Dynamic Web Applications or Enterprise Applications.
If it is not present or shown Empty then you have to Download the Server
i.e Apache Tomcat or Weblogic or any other server and have to link in the New RunTime Button Link.
Next Click on Next and Finish.
Below is the Final Structure of the project.
You need to create below files:
1. Login and Success Servlet Class.
2. home and success.jsp for the login page and if credentials are correct then forward it to the success page.
Step 2:
Create home.jsp file under webContent.
Content of home.jsp file.
It contains the code for Simple Login Form.
<form action="Login" method="post">Here action means when user submit this form then Login Servlet will be invoked and it find the post method in the Login Servlet
<%@ page language="java"
contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert
title here</title>
</head>
<body>
<h1>Login form</h1>
<div>
<form action="Login"
method="post">
<table>
<tr>
<td>Name :</td>
<td><input type="text" name="userName"
/> </td>
</tr>
<tr>
<td>Password
:</td>
<td><input type="password" name="userPass"/></td>
</tr>
<tr>
<td><input type="submit" value="login"
/></td>
</tr>
</table>
</form>
</div>
</body>
</html>
home.jsp file snapshot
Step 3:
Create Login.java Servlet
Login Servlet:
package
com.studyskymate.dinesh.servlet.login;
import
java.io.IOException;
import
java.io.PrintWriter;
import
javax.servlet.RequestDispatcher;
import
javax.servlet.ServletException;
import
javax.servlet.annotation.WebServlet;
import
javax.servlet.http.HttpServlet;
import
javax.servlet.http.HttpServletRequest;
import
javax.servlet.http.HttpServletResponse;
@WebServlet("/Login")
public class Login extends
HttpServlet {
private static final long serialVersionUID = 1L;
public Login()
{
super();
}
protected void
doPost(HttpServletRequest request,
HttpServletResponse response) throws
ServletException, IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
String name=request.getParameter("userName");
String password=request.getParameter("userPass");
if(name.equals("dinesh")
&& password.contentEquals("1234") ) {
RequestDispatcher rd =request.getRequestDispatcher("success");
//To handle it you need to create success servlet which we will create in next step
rd.forward(request, response);
}else {
out.print("Sorry
Invalid UserName or Password !");
RequestDispatcher rd=request.getRequestDispatcher("/home.jsp");
rd.include(request, response);
}
}
}
----------------------------------------------------------------------------------------------------------
Step 4
Create Success.java Servlet Similarly:
It will Invoke Login Servlet and if username and password are correct then it will forward the request to Success.jsp
import
java.io.IOException;
import
java.io.PrintWriter;
import
javax.servlet.RequestDispatcher;
import
javax.servlet.ServletException;
import
javax.servlet.annotation.WebServlet;
import
javax.servlet.http.HttpServlet;
import
javax.servlet.http.HttpServletRequest;
import
javax.servlet.http.HttpServletResponse;
@WebServlet("/success")
public class Success
extends HttpServlet {
private static final long serialVersionUID = 1L;
public
Success() {
super();
}
protected void
doPost(HttpServletRequest request, HttpServletResponse response) throws
ServletException, IOException {
response.setContentType("text/html");
PrintWriter out= response.getWriter();
RequestDispatcher rd=request.getRequestDispatcher("/success.jsp");
rd.forward(request, response);
}
}
-----------------------------------------------------------------------------------------------------------------
Step 5.
Create success.jsp to capture the response from Success Servlet.
<%@ page language="java"
contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert
title here</title>
</head>
<body>
<div>
<h1>Welcome <font color="red"><%=request.getParameter("userName") %> </font> </h1>
<h2>You are
Valid User</h2>
<a href="/WebProject/home.jsp"><button type="button">Home Page</button></a>
</div>
</body>
</html>
----------------------------------------------------------------------
Step 6
web.xml file.
6.1 create web.xml file under WEB-INF folder if not present.
6.2 Add welcome file home.jsp or your index file statement in the web.xml
as below:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
<display-name>WebProject</display-name>
<welcome-file-list>
<welcome-file>home.jsp</welcome-file>
</welcome-file-list>
</web-app>
--------------------------------------------------------------------
Step 7:
Run your project on Server.
Below Login Form will open after running the server at your browser.
Enter the correct Username and password.
In my case, it is dinesh and 1234 because I have provided these validations in Login Servet.
Now It will Invoke Login Servlet and if username and password is correct then it will forward the request to Successjsp
In the case of Wrong credentials, it will include the output of login servlet and forward the request to home.jsp
Thanks
