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Sorting on the basis of multiple fields
function sortObjects(arr) {
arr.sort(function(a, b) { if (a.adviserid < b.adviserid) { return -1; } else if (a.adviserid > b.adviserid) { return 1; } else { if (a.cutomer_id < b.cutomer_id) { return -1; } else if (a.cutomer_id > b.cutomer_id) { return 1; } else { if (a.account_id < b.account_id) { return -1; } else if (a.account_id > b.account_id) { return 1; } else { if (a.product_type === b.product_type) { if (a.account_id > b.account_id) { return -1; } else if (a.account_id < b.account_id) { return 1; } } return 0; } } } }); // Group the array by adviserid var groupedArr = []; var currentAdviserId = null; for (var i = 0; i < arr.length; i++) { var obj = arr[i]; if (obj.adviserid !== currentAdviserId) { currentAdviserId = obj.adviserid; groupedArr.push([]); } groupedArr[groupedArr.length - 1].push(obj); } return groupedArr; }
Here's how you would use this function:
// Example array of objects var arr = [ { adviserid: 1, cutomer_id: "abc", account_id: 10, product_type: "A" }, { adviserid: 1, cutomer_id: "abc", account_id: 20, product_type: "A" }, { adviserid: 1, cutomer_id: "def", account_id: 30, product_type: "B" }, { adviserid: 2, cutomer_id: "ghi", account_id: 40, product_type: "A" } ]; // Call the function to sort the array var sortedArr = sortObjects(arr); // Print the sorted array console.log(sortedArr);
In this example, the arr array contains four objects with adviserid, cutomer_id, account_id, and product_type properties. The sortObjects function sorts the array based on the three fields you specified (in ascending order), and then groups the sorted array by adviserid. The sorted and grouped array is then printed to the console.
In the sorting logic, the function first sorts by adviserid, then by cutomer_id, and then by account_id. If two objects have the same product_type, they are sorted by account_id in descending order. If two objects have the same adviserid, they are grouped together in the output array.
Sure, here's an example JavaScript function that sorts an array of objects based on the three fields you specified:
function sortObjects(arr) { arr.sort(function(a, b) { if (a.adviserId < b.adviserId) { return -1; } else if (a.adviserId > b.adviserId) { return 1; } else { if (a.priority < b.priority) { return -1; } else if (a.priority > b.priority) { return 1; } else { if (a.accountId < b.accountId) { return 1; } else if (a.accountId > b.accountId) { return -1; } else { return 0; } } } }); return arr; } // Example array of objects var arr = [ { adviserId: 2, priority: 1, accountId: 10 }, { adviserId: 1, priority: 2, accountId: 20 }, { adviserId: 1, priority: 2, accountId: 30 }, { adviserId: 2, priority: 1, accountId: 40 } ]; // Print the input array console.log("Input: ", arr); // Call the function to sort the array var sortedArr = sortObjects(arr); // Print the sorted array console.log("Output: ", sortedArr);
In this example, the arr array contains four objects with adviserId, priority, and accountId properties. The sortObjects function sorts the array based on the three fields you specified, with priority being sorted in ascending order. If two objects have the same priority, they are sorted by accountId in descending order. The input and output arrays are then printed to the console.
The output of this function will be:
Input: [ { adviserId: 2, priority: 1, accountId: 10 }, { adviserId: 1, priority: 2, accountId: 20 }, { adviserId: 1, priority: 2, accountId: 30 }, { adviserId: 2, priority: 1, accountId: 40 } ] Output: [ { adviserId: 1, priority: 2, accountId: 30 }, { adviserId: 1, priority: 2, accountId: 20 }, { adviserId: 2, priority: 1, accountId: 40 }, { adviserId: 2, priority: 1, accountId: 10 } ]
Create a Digital Clock using HTML and JavaScript
Create a Digital Clock using HTML and JavaScript <! DOCTYPE html> < html > < head > ...
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